What is the Solution to the Equation (ArcSinx)^3+(ArcCosx)^3 = a?

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hadi amiri 4
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(ArcSinx)^3+(ArcCosx)^3=a
discuss on a:rolleyes:
 
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[tex]a = \frac{ \pi ( 6 \arcsin x - 3\pi )^2}{24} + \frac{3\pi^3}{96}[/tex]
 

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