What is the solution to the Moving Blocks Problem?

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Homework Help Overview

The problem involves two blocks connected by a massless string over a frictionless pulley, with one block on a horizontal surface and a force applied at an angle. The objective is to determine the upward acceleration of the second block.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the net force on the first block and assumes the accelerations of both blocks are the same. Questions arise regarding the inclusion of the weight of the second block in the net force equation.

Discussion Status

Participants are actively discussing the assumptions made in the original poster's calculations. Some guidance has been offered regarding the role of the second block's weight in the net force on the first block, indicating a productive exploration of the problem.

Contextual Notes

The original poster's calculations are based on specific values for mass, force, and friction, but there is a lack of clarity regarding the correct interpretation of forces acting on both blocks.

zzinfinity
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Homework Statement



I'm stuck on this one,

A 32.5-kg block (m1) is on a horizontal surface, connected to a 6.9-kg block (m2) by a massless string as shown in the Figure. The pulley is massless and frictionless. A force of 223.3 N acts on m1 at an angle of 30.1o. The coefficient of kinetic friction between m1 and the surface is 0.213. Determine the upward acceleration of m2.

Homework Equations





The Attempt at a Solution


I determined the net force on m1 as follows

F=223.3Cos(30.1)-(m1*g-223.3Sin(30.1))*.213 - m2*g.

Then I determined the acceleration of m1 by dividing the net force by 32.5kg. I assumed that the acceleration of m1 and m2 should be the same so i got an answer of 2.51 m/s^2.

The online homework says this is wrong, what am I missing?

Thanks!
 
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figure?
 
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zzinfinity said:
I determined the net force on m1 as follows

F=223.3Cos(30.1)-(m1*g-223.3Sin(30.1))*.213 - m2*g.

Why is the term m2*g in the above equation?
 
The weight of m2 creates tension on the rope, which exerts a rightward force on m1, so don't you have to factor that into the net force on m1? m2*g is the weight of m2.
 
zzinfinity said:
The weight of m2 creates tension on the rope, which exerts a rightward force on m1

The above is correct but the rest of the statement is not correct.

You will see why it is not correct if you consider m2. Is not m2 accelerating upwards?
 
Thanks! got it.
 

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