What is the speed of a box pulled by a tension force after a given time?

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SUMMARY

The discussion centers around calculating the speed of a box with a mass of 10 kg being pulled by a tension force represented as T = 75 ˆx + 25 ˆz N after 0.05 seconds on a frictionless surface. The key equation used is pf = pi + Fnet * dt, which simplifies to vf = (Fnet * dt) / m. The primary challenge highlighted is understanding vector notation and calculating the magnitude of the force to determine the final speed of the box.

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Homework Statement



4. A box of mass M=10 kg is at rest on a frictionless level surface (like an ideally smooth
ice rink). A rope tied to the box is pulled horizontally, such that the tension in the rope is
(vector-->)T = 75 ˆx + 25 ˆz N, where both the x-axis and the z-axis are parallel to the floor. What is
the speed of the box after 0.05 seconds?
1. 0.395 m/s
2. 0.264 m/s
3. 0.198 m/s
4. 0.158 m/s
5. 0.132 m/s
6. 0.000 m/s



Homework Equations



pf = pi +Fnet*dt

The Attempt at a Solution



I know how to solve this problem, I'm just having trouble when it comes to the vectors in this case.

Pf = pi + Fnet*dt
{pi = 0) so..

Pf = Fnet*dt

p = mv

mvf = Fnet* dt

vf = (Fnet *dt)/m

But I'm stuck on the vectors...please help!
 
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I don't quite understand your notation... Can you explain them?

This question is quite fundamental... Since the force is given in vector form, you must first find the magnitude of the force. It should be clear where you should be heading to afterwards.
 
Notation for which part?
 

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