What Is the Speed of a Charged Ball Exiting a Box?

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Homework Help Overview

The discussion revolves around a physics problem involving a charged ball entering and exiting a box, with specific parameters such as mass, charge, initial speed, and voltage difference. The subject area includes concepts of energy conservation, kinetic energy, and electrostatic potential energy.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculations related to energy changes as the ball moves through the box, questioning whether the ball gains or loses energy. There are attempts to clarify the implications of the energy calculations, particularly regarding the ball's kinetic energy after exiting the box.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the energy changes involved. Some participants express confusion about the implications of the energy calculations, particularly regarding the possibility of the ball having negative kinetic energy and what that might mean for its motion.

Contextual Notes

There is mention of a potential typo in the calculations, and participants are trying to reconcile the energy changes with the physical behavior of the ball, including whether it can exit the box under the given conditions.

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Homework Statement


A small ball has mass 3.4x10^-8 kg and charge of 2.0x10^-5 C. It enters a box with initial speed 1.2x10^4 m/s. The point where the charge leaves the box is at a voltage 350kV higher than the entry point. Find the speed of the ball as it leaves the box. [/B]

Homework Equations


ΔE = E - E0

ΔE = q(V)

E = 1/2mv2

The Attempt at a Solution


[/B]
E = 1/2 (3.4x10-8)(1.2x104)2 = 2.448 J
ΔE = (2.0x10-5)(350000)= 7 J
7J = E - 2.448J

9.448J = 1/2(3.4x10-8)v2

v = sqrt ((2(9.448))/(3.4x10-8)

v = 23577 m/s

Does this look right? Apparently the ball doesn't leave the box. But that doesn't make any sense to me.
 
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nmsurobert said:
ΔE = (2.0x10-5)(350000)= 7 J
Has it gained or lost electrostatic energy?
 
nmsurobert said:
E = 1/2 (3.4x10-8)(2.0x10-5)2
I assume the (2.0x10-5) is a typo.
 
It's lost energy because the charge is positive, right?

I don't believe it a typo. I'm helping someone with their homework. Their instructor said the ball doesn't leave the box. But that makes no sense to me.
 
That is a typo. I just saw what I did wrong.
 
But even with that 2.448 is correct. I put it in my calculator correctly but I typed it wrong.
 
nmsurobert said:
It's lost energy
Quite so. So what is the new KE?
 
Should it have been 4.55 and not 9.44?
 
nmsurobert said:
It's lost energy
I'm sorry, I misremembered which way round I asked the question. I should have said that answer was wrong.
It is a positive charge which has moved to a point at a higher potential. It has gained electrostatic energy.
 
  • #10
Ok. That doesn't help me though. I'm confused about what you're trying to get at.
 
  • #11
nmsurobert said:
Ok. That doesn't help me though. I'm confused about what you're trying to get at.
If it started with 2.448J KE and gained 7J PE with no work being done on it, how much KE does it now have?
 
  • #12
-4.552J?
 
  • #13
nmsurobert said:
-4.552J?
Right. What does that tell you?
 
  • #14
Does that mean that the ball stopped?
 
  • #15
nmsurobert said:
Does that mean that the ball stopped?
Is it possible for the ball to exit with negative KE?
 
  • #16
Wouldn't that mean the ball turned around. You can't have negative mass so it has to have negative direction.
 
  • #17
nmsurobert said:
Wouldn't that mean the ball turned around. You can't have negative mass so it has to have negative direction.
Energy is a scalar. No matter which way it is moving it cannot have negative KE.
 

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