What is the speed of an electron in the Bohr model of the hydrogen atom?

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SUMMARY

In the Bohr model of the hydrogen atom, the speed of an electron is calculated using the formula v = n(h/2π)/(rm), where h is Planck's constant (6.63e-34 J·s) and m is the mass of the electron (9.11e-31 kg). For a radius of 5.3e-11 m, the velocity is expressed as v = 0.218n m/s, where n is an integer representing the principal quantum number. A correction in the radius from 5.3e-4 m to 5.3e-11 m significantly impacts the calculated velocity, leading to more realistic values for electron speed.

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[SOLVED] speed of electrons

Homework Statement



In the Bohr model of the hydrogen atom, an electron circles a proton at a radius of 5.3e-11 m. How fast must the electron be moving if the centripetal acceleration is to be supplied by Coulombic attraction?

Homework Equations



L=n(h/2pi) where h is Plancks constant and n is an integer

L=rmv


The Attempt at a Solution



n(h/2pi)=rmv

v=n(h/2pi)/(rm)

v= n(6.63e-34/2pi)/(5.3e-4)(9.11e-31)

v= 0.218n m/s

Now that velocity seems way to small for a speed of an electron...

Any help is appreciated! Thanks!
 
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v= n(6.63e-34/2pi)/(5.3e-4)(9.11e-31)

Why is this a 4 instead of an 11?
 
Thank you...My 11 looked like a 4 in my notes...simple mistakes can kill you! haha

I got a very large velocity now so the answer makes more sense.
 

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