What is the speed of the objects in a pulley system?

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    Pulley Speed
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Homework Help Overview

The problem involves a pulley system with two objects connected by a string, where one object is released from a height and the goal is to determine the speed of each object just before one hits the ground. The context includes gravitational acceleration and the initial height of the released object.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using energy conservation principles, specifically the relationship between potential energy and kinetic energy. There are attempts to derive the speed using equations, with some questioning the assumptions made about potential energy at the final state.

Discussion Status

Participants are actively engaging with the problem, sharing their calculations and questioning the assumptions regarding potential energy. Some guidance has been offered to clarify the approach, but multiple interpretations of the problem are being explored without a clear consensus on the correct method.

Contextual Notes

There is a mention of needing additional information, such as the mass of the other object and the angle theta, which are not provided in the original problem statement. Participants are also addressing the implications of assuming final potential energy is zero.

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Finding speed with a pulley?

Homework Statement



Two objects are connected by a light string
passing over a light frictionless pulley as
shown in the figure. The 5.9 kg object is
released from rest at a point 4.53 m above the
floor.
The acceleration of gravity is 9.8 m/s2 .

What is the speed of the each object at
the instant before the 5.9 kg hits the floor?
Answer in units of m/s.

Homework Equations





The Attempt at a Solution


I use the energy equation where
PE(initial)=KE(final)
and solve for v but it does not seem to work
 
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decrease in PE = increase in KE
 
Welcome to PF!

Hi physics10189! Welcome to PF! :wink:
physics10189 said:
I use the energy equation where
PE(initial)=KE(final)
and solve for v but it does not seem to work

Show us your full calculations, and then we can see what went wrong, and we'll know how to help! :smile:
 


well here is what i did

mgh=.5mv^2
h=Lcos(theta)
mass cancel out
so this is what i came up with
v=2gLcos(theta)
where L=10m of the string's length
 


whoops wrong problem
scrath the last reply

ok its the same way kinda
so here is what i did

PE(initial)=KE(final)
mgh=.5mv^2

masses cancel out
h=4.53m
there for
v=sqrt(2gh)
 


Is the "final" PE of the system zero?
See my earlier post.
 


yes because just before the blocks hit the ground can we assume that the height is zero therefore the PE final is zero?
 


What answer are you getting?
 


A figure, or description, showing what is theta, the mass of the other object, etc., sure would help.
 

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