What is the spring force constant k for a ball dropped onto a spring?

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SUMMARY

The spring force constant k for a 142 g ball dropped from a height of 62.2 cm onto a spring with a maximum compression of 4.35501 cm is calculated to be 19.875 N/m. The relevant equations include gravitational potential energy (mgh) and the spring force equation (F = -kx). The correct approach involves equating the gravitational potential energy to the elastic potential energy stored in the spring, rather than directly using force equations.

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irbombardmnt
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Please help me out, I'm new here, and I only have one more attempt on this problem, totally lost.

Homework Statement



A(n) 142 g ball is dropped from a height of 62.2 cm above a spring of negligible mass. The ball compresses the spring to a maximum displacement of 4.35501 cm. The acceleration of gravity is 9.8 m/s^2 . Calculate the spring force constant k. Answer in units of N/m.

Homework Equations


F=-kx


The Attempt at a Solution


mgh=-kx
(.142)(9.8)(.622)=-k(0.435501)
k=19.875

?
 
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You're setting energy equal to force. Instead of the force of the spring, use the potential energy of the spring.
 
Hi irbombardmnt, welcome to PF.
Your relevant equation is not correct. mgh is the fall of potential. kx is not the energy.
What is the formula for the energy stored in a stretched spring?
In fact ball falls through h+x distance before it comes to rest.
 

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