# What is the strength of a delta function.

1. Jun 1, 2012

### jk_zhengli

Hi all,

"If g(t) starts with a delta function of strength Y/2, then...."

I wonder what that means. Does it mean g(t) = 0.5Yδ(t) ?

Thanks

2. Jun 1, 2012

### micromass

Staff Emeritus
Yes. It means that

$$\int_{-\infty}^{+\infty} g(t)dt=\frac{Y}{2}$$

So it coincides with $\frac{Y}{2}\delta (t)$.