What is the strength of a delta function.

[jk_zhengli]

Hi all,

I read the following:

"If g(t) starts with a delta function of strength Y/2, then..."

I wonder what that means. Does it mean g(t) = 0.5Yδ(t) ?

Thanks

 

[micromass]

Yes. It means that

$$\int_{-\infty}^{+\infty} g(t)dt=\frac{Y}{2}$$

So it coincides with $\frac{Y}{2}\delta (t)$.