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What is the strength of a delta function.

  1. Jun 1, 2012 #1
    Hi all,

    I read the following:

    "If g(t) starts with a delta function of strength Y/2, then...."

    I wonder what that means. Does it mean g(t) = 0.5Yδ(t) ?

    Thanks
     
  2. jcsd
  3. Jun 1, 2012 #2

    micromass

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    Yes. It means that

    [tex]\int_{-\infty}^{+\infty} g(t)dt=\frac{Y}{2}[/tex]

    So it coincides with [itex]\frac{Y}{2}\delta (t)[/itex].
     
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