What is the support reaction at E for the 9m length beam?

[MMCS]

Calculate the support reactions at B and E for the 9m length beam shown below.
I have the answers at 4.71KN and 1.79KN but it is old work that i am revising and i can't remember how i got to them. One of the supports not being at the end is throwing me off. If anyone could show a rough working out it would be appreciated.

 

[PhanthomJay]

You should refresh your memory on the 3 equilibrium equations
$\Sigma F_x = 0, \Sigma F_y = 0,$ and $\Sigma M_{any-point} = 0$.

There is nothing going on in the x direction, so you just need the last 2 equations. The reaction forces must add up to the applied loads; but the key is summing moments about a point = 0 (hint: choose one of the reaction points as your point to sum moments about. Watch plus/minus signs).

Please show an attempt at a solution for further assistance.

 

[MMCS]

Hi thanks for your reply

I have (-1500 x 2) + (-3000 x 4) + (-2000 x 9) + 7B = 0
-33000 + 7B + E= 0
B = 33000/7
B = 4714N

I don't know where to go next to calculate E?

 

[PhanthomJay]

Hi thanks for your reply

I have (-1500 x 2) + (-3000 x 4) + (-2000 x 9) + 7B = 0
-33000 + 7B + E= 0
B = 33000/7
B = 4714N

I don't know where to go next to calculate E?

Yes, good. For E, the sum of forces in the vertical y direction must be zero. That will give you E. You can also find E by summing moments about B. That serves as a good check on your work.