What is the temperature increase of the gas?

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SUMMARY

The discussion focuses on calculating the temperature increase of gas in a rubber raft after performing work on it using an air pump. The work done on the gas is determined to be 0.32 J, calculated using the formula Work = Force * Distance. Assuming all work converts to thermal energy, the temperature increase can be calculated using the ideal gas law and specific heat capacity, with initial conditions set at 293 K. The relevant equations include P*V=n*R*T and Delta T = Q/c*m.

PREREQUISITES
  • Understanding of the Ideal Gas Law (P*V=n*R*T)
  • Knowledge of thermodynamics, specifically work and heat transfer
  • Familiarity with specific heat capacity (c) and its units
  • Basic algebra for manipulating equations and solving for variables
NEXT STEPS
  • Learn about the Ideal Gas Law and its applications in real-world scenarios
  • Study the principles of thermodynamics, focusing on work and energy transfer
  • Explore specific heat capacity calculations and their significance in thermal energy changes
  • Investigate the relationship between pressure, volume, and temperature in gases
USEFUL FOR

Students studying physics, particularly those focusing on thermodynamics and gas laws, as well as educators seeking to explain the concepts of work and thermal energy in gases.

Tori Grafe
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Homework Statement


In an empty rubber raft the pressure is approximately constant. You push on a large air pump that pushes 1.0L (1.0×10^−3 m^3) of air into the raft. You exert a 16N force while pushing the pump handle 2.0×10^−2 m .

Part A: Determine the work done on the gas.
Part B: If all of the work is converted to thermal energy of the 1.0 L of gas, what is the temperature increase of the gas? Assume that the air obeys the ideal gas law and is initially at 293 K.

2. Homework Equations

Just trying to come up with some equations that may help, although I have had no luck...
P*V=n*R*T
Work = -n*R*deltaT
W= (-/+) deltaP*V
Delta T = Q/c*m
Uthermal = 3/2*n*R*T
delta U = c*m*delta T

The Attempt at a Solution


Part A: I have already solved this part as you can see below...
Work = Force * Distance
Work = 16 N * 2.0x10^-2 m
Work = .32 N*m
Work = .32 (kg*m^2)/s^2
Work = .32 J

Part B: I have attempted a couple of times as you can see below... I really need help on this
Work = Q
Delta T = Q/c*m
m = ro * v
ro = 1.3 kg/m^3
v= 1.0x10^-3 m^3
c= 700 J/(kg * degrees C)
m = 1.3x10^-3 kg

delta T = .32J / (700 (J/(kg * degrees C)) * 1.3x10^-3 kg)

Work = -delta P * v
.32 J = -delta P * 1.0x10^-3
-delta P = 320 N/m^2
320 N/m^2 = n*R*delta T
320 N/m^2 = n*(8.314 J/mol * K)*delta T
 
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I think the equation
ΔU=nCvΔT
Might help you.
 

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