What Is the Time to Maximum Speed in a Simple Pendulum?

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SUMMARY

The time to maximum speed in a simple pendulum can be calculated using the formula for frequency, f = 1/2π (g/l)^(1/2), where g is the acceleration due to gravity and l is the length of the pendulum. For a pendulum with a length of 0.773 meters, the frequency is approximately 1.76 Hz, leading to a time of 0.142 seconds for the pendulum to reach maximum speed after a quarter of a full oscillation. The maximum speed occurs when the pendulum is vertical for the first time, confirming the initial hypothesis. Calculations involving kinetic and potential energy can also provide insights into the pendulum's motion.

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eatingblaa
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1. A simple pendulum is made from a 0.773-m-long string and a small ball attached to its free end. The ball is pulled to one side through a small angle and then released from rest. After the ball is released, how much time elapses before it attains its greatest speed?



2. f = 1/2pi (g/l)^1/2



3. I thought that maximum speed would be when the string is vertical for the first time.
This would be when the pendulm had gone through 1/4 of a full oscillation.

So I calculated f =.567s
and 1/4 f = .142s,

But this is wrong,

Am I on the right track or way off?
 
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eatingblaa said:
I thought that maximum speed would be when the string is vertical for the first time.
This would be when the pendulm had gone through 1/4 of a full oscillation.
You thought well, but I don't think you did the calculation right. If I use the formula you provided, I get a frequency which is about 10 times larger. So you might want to redo the number crunching :smile:
 
I have seen some problems like this that have to do with Kinetic Energy.

Ek=1/2mv² so if you have any of the values for this, u can isolate for v like this:

v=√2(Ek)/m

OR.. If u can only work with potential energy you could use this equation

v=√2g▲h

▲h will be the change in height.. but ur looking for time.. so.. hmm.

You may need an equation that has "t" in it.. like P=w/t... if u could find the work done.. or something.. i don't know.. lol.. hope any of this helps.. sorry, I am just starting physics! :)
 

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