What is the torque needed to open a 2000kg door?

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Discussion Overview

The discussion revolves around calculating the torque required to open a 2000kg door, considering its dimensions and the assumption of negligible friction. Participants explore the relationship between torque, angular velocity, and acceleration in the context of this problem.

Discussion Character

  • Exploratory, Technical explanation, Mathematical reasoning

Main Points Raised

  • One participant proposes that the torque needed to open the door can be calculated using the formula 2000(1.5)(9.81), where 1.5 is the distance from the hinge to the center of gravity.
  • Another participant suggests that if friction is negligible and the hinges are perfectly aligned, any amount of torque will suffice to open the door.
  • A later reply specifies a desired opening time of ten seconds for the door.
  • Another participant introduces the angular equivalent of Newton's laws, stating that torque equals moment of inertia times angular acceleration, and offers to provide further assistance if needed.

Areas of Agreement / Disagreement

Participants express differing views on the specifics of torque calculation and the implications of friction and hinge alignment. The discussion remains unresolved regarding the exact torque needed and the method of calculation.

Contextual Notes

Assumptions about friction and hinge alignment are critical to the discussion, and the relationship between torque, moment of inertia, and angular acceleration is not fully explored.

Who May Find This Useful

Individuals interested in mechanics, particularly those exploring torque calculations and angular motion in practical applications.

steve_5959
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My door is 2000kg, it is 3m wide, 4m high and is on a hinge. for the moment i am saying that friction is negligable. How much torque is required to open my door. I have already said that the torque needed to open the door is acting through the C.O.G so it is 2000(1.5)(9.81), i don't know if that is correct though, please help :) If I can find this then I can find out the angular velocity and acceleration
 
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If friction is negligible and the door hinges are perfectly aligned, then any amount of torque will open the door.

How fast do you want the door to open?
 
want door to open in ten seconds.
 
You could apply the angular equal of Newton's laws for linear motion:

F = ma
torque = moment of inertia X angular acceleration
angular acceleration = change in angle / change in time.

Let me know if you need any help with this.
 

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