What is the Use of the Constant in the Integral?

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Homework Help Overview

The discussion revolves around the use of a constant in the context of an integral related to the function defined as \( f(x) = \int_{t=p}^{t=x} \frac{\cos t}{t} dt \). Participants are exploring the implications of the constant and the specific value of \( f(3) = 4 \).

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the role of the constant in the integral, particularly when evaluating at specific points. There is also a discussion about the starting point of the integral and its implications for the value of the function at \( x = 3 \).

Discussion Status

Some participants have offered insights regarding the constant added to the integral and its significance when evaluating the function at a specific point. Multiple interpretations of the role of the constant and the derivative of the function are being explored.

Contextual Notes

There is a mention of a potential oversight regarding the derivative notation and the starting point of the integral, which may affect the understanding of the function's behavior.

songoku
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Homework Statement
Find f(x) where ##f(x)=\frac{\cos x}{x}## and f(3) = 4. State the answer in form of ##f(x)=\int_{t=p}^{t=q} (........)##
Relevant Equations
Fundamental Theorem of Calculus
This is my attempt:
$$f(x)=\int_{t=p}^{t=x} \frac{\cos t}{t} dt$$

But I am not sure what ##p## is and what the use of ##f(3)=4##

Thanks
 
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You forgot about the constant that is added to the integral. If you start the integral at p=3, then you know that the integral part is 0 at x=3. So what constant is added to the integral?
 
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songoku said:
Homework Statement:: Find f(x) where ##f(x)=\frac{\cos x}{x}## and f(3) = 4. State the answer in form of ##f(x)=\int_{t=p}^{t=q} (...)##
Did you forget to add the prime? Shouldn't it be ##f'(x) = \frac{\cos x}{x}##?
 
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FactChecker said:
You forgot about the constant that is added to the integral. If you start the integral at p=3, then you know that the integral part is 0 at x=3. So what constant is added to the integral?
I understand

Mark44 said:
Did you forget to add the prime? Shouldn't it be ##f'(x) = \frac{\cos x}{x}##?
Yes, I am sorry

Thank you very much FactChecker and Mark44
 

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