What is the value of secx when sinx = -0.40 and tanx > 0?

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    Trigonometry
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Homework Help Overview

The problem involves finding the value of sec(x) given that sin(x) = -0.40 and tan(x) > 0. The context is trigonometric functions and their relationships in different quadrants.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the given values for sin(x) and tan(x), considering the quadrants where these conditions hold. There is an attempt to determine the angle corresponding to sin(x) and how to derive sec(x) from it.

Discussion Status

Some participants are exploring the quadrant implications of the sine value and the tangent condition. Guidance is being sought on how to calculate sec(x) from the known sine value.

Contextual Notes

There is a mention of multiple angles corresponding to the sine value, indicating a need to clarify which quadrant is relevant for the problem. The discussion reflects uncertainty about the correct approach to find sec(x).

Xtremeownage
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If sinx = -0.40 and tanx > 0, then secx, to the nearest hundreth, is

A) 0.92

B) -0.92

C) -1.09

D) 1.09

So I figured that sin^-1 = -23.57817848, but I don't know how to get sec, can someone help!
 
Last edited:
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I would assume it is in the 3rd quadrant as well
 
There are 2 angles for x that correspond to sin(x) = -0.40
the one you found is in the 4th quadrant, there is one in the 3rd quadrant as well
 
Thanks, Ill try solving it now
 

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