What is the velocity of the object after it has been displaced by the spring?

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Homework Help Overview

The discussion revolves around a physics problem involving a spring and the velocity of an object after being displaced by the spring. The context includes concepts related to work, kinetic energy, and potential energy in a frictionless environment.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between work done by the spring and the change in kinetic energy. There are attempts to clarify the use of the spring constant and the implications of a frictionless surface on energy conservation. Questions arise regarding the calculation of work and whether certain energy changes are zero.

Discussion Status

The discussion is ongoing, with various participants contributing thoughts on the relationships between work, potential energy, and kinetic energy. Some guidance has been offered regarding the equations involved, but no consensus has been reached on the specific values or outcomes.

Contextual Notes

Participants are navigating the constraints of the problem, including the absence of a defined spring constant and the implications of a frictionless tabletop on energy calculations.

GreenPrint
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Homework Statement



http://img205.imageshack.us/img205/7536/capturebb.jpg

i am stuck on part c

how do i find work without using the spring constant





Homework Equations



work equals force parallel times displacement at which the force is acted during...

Work done by spring = .5 kx^2
Work = delta K

but delta K = 0 because the table top is frictionless

Work = delta U
delta U = 0 in this situation correct?

The Attempt at a Solution



so I'm stuck...

i think it might be zero but .5 kx^2 would not give zero now would it...
 
Last edited by a moderator:
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The work done on the block by the spring is equal to the change in KE of the block.
 
hmmmmmmmm... so then... um...
 
ok thanks
 
wait so to find the spring constant...

is delta U = delta K = W = .5 kx^2

?
 
- (Mg)/(2h)
 
GreenPrint said:
wait so to find the spring constant...

is delta U = delta K = W = .5 kx^2

?
0.5 kx^2 = 0.5 Mv^2.
From the given data you can find v.
 

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