What is the velocity of the object after it has been displaced by the spring?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
6 replies · 2K views
GreenPrint
Messages
1,186
Reaction score
0

Homework Statement



http://img205.imageshack.us/img205/7536/capturebb.jpg

i am stuck on part c

how do i find work without using the spring constant





Homework Equations



work equals force parallel times displacement at which the force is acted during...

Work done by spring = .5 kx^2
Work = delta K

but delta K = 0 because the table top is frictionless

Work = delta U
delta U = 0 in this situation correct?

The Attempt at a Solution



so I'm stuck...

i think it might be zero but .5 kx^2 would not give zero now would it...
 
Last edited by a moderator:
Physics news on Phys.org
The work done on the block by the spring is equal to the change in KE of the block.
 
wait so to find the spring constant...

is delta U = delta K = W = .5 kx^2

?
 
GreenPrint said:
wait so to find the spring constant...

is delta U = delta K = W = .5 kx^2

?
0.5 kx^2 = 0.5 Mv^2.
From the given data you can find v.