What is the Voltage Between Point B and Point C in this Circuit?

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SUMMARY

The voltage between point B and point C in the described circuit can be calculated using the potential divider rule. The battery voltage is 107.5 V, and the circuit consists of two resistors in parallel followed by a third resistor. The voltage at point C with respect to the negative terminal of the battery is determined by the formula Vc = Vbat * R2/(R1+R2). Consequently, the voltage difference Vb - Vc can be expressed as Vb - (Vbat * R2/(R1+R2)).

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A battery has a voltage of 107.5 V. We denote this battery with point B. Point C is the point after two resistors, which are parallel to one another. Immediately after point C we get one more resistor. Calculate the voltage between B and C.

I calculated the total resistance between B and C and from there, I calculated the voltage. However my teacher says that I should take resistor 3, which is situated after point C. Is it just me, or is he wrong?
 
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It's hard to interpret what your circuit looks like from the description but it looks like

Battery +ve --- Point B --- 2 resistors in parallel --- Point C ---- one resistor --- Battery -ve

If that is correct..

Step 1 Convert the two resistors in parallel to one..

Battery +ve --- Point B --- one resistor(R1) --- Point C ---- one resistor(R2) --- Battery -ve

Then the voltage at point C with respect to the battery -ve can be calculated using the potential divider rule..

Vc = Vbat * R2/(R1+R2)

The voltage requested Vb-Vc = Vbat - Vc = Vb - (Vbat * R2/(R1+R2))
 

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