What is the Volume of a Parallelepiped with Given Sides and Unknown Constant?

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Homework Help Overview

The discussion revolves around finding the volume of a parallelepiped defined by three vectors, with one of the vectors containing an unknown constant represented by λ. The vectors are given in a specific format, and there is some confusion regarding the representation of the constant and its implications for the volume calculation.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the meaning of the variable 'a' in the context of the vectors and question how it relates to λ. There are attempts to clarify the notation used for the vectors and the implications of substituting λ into the volume formula. Some participants suggest using the triple product of vectors to find the volume, while others express confusion over the representation of λ and its dimensionality.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the problem's setup and notation. Some guidance has been offered regarding the use of the triple product and the need for clear definitions of the variables involved. However, there is no consensus on the interpretation of the problem or the correct approach to take.

Contextual Notes

There is ambiguity regarding the representation of λ and its dimensionality, as well as the notation used for the vectors. Participants are encouraged to clarify the problem statement and the definitions of the variables to facilitate further discussion.

teng125
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Find the volume of the parallelepiped depending on λ with

a=[2a,2 ,2] b=[4,1,a] c=[2,2,a] where a=[-3,1]


the [-3,1] is it let says (x,y,z) represents x and z for my substitution to find volume??
since there is no variable in y??
 
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somebody pls help
 
teng, is this the direct copy of the question from the book? Because I can't figure out what the 'a' term is supposed to represent... especially since, given the context in the coordinates of A, B, and C, I would expect 'a' to be a number
 
a is equals to 'lamda' sign
 
teng125 said:
Find the volume of the parallelepiped depending on λ with

a=[2a,2 ,2] b=[4,1,a] c=[2,2,a] where a=[-3,1]


the [-3,1] is it let says (x,y,z) represents x and z for my substitution to find volume??
since there is no variable in y??

You've actually used a in 3 different ways! I can guess that the "a" inside the brackets should really be [itex]\lambda[/itex] but then what does "a= [-3,1] mean??

Please don't make people guess what you mean.

My first guess at your notation is that [2a,2,2], [4,1,a], and [2,2,a] are vectors with the direction and length of the concurrent sides of the parallelopiped. If that is what is meant, please say so!

I have no guess at all as to what "a= [-3,1]" could mean. Do you know the "triple product" of vectors? This problem looks made for that.

If you don't, do you know that the cross product of two vectors, u, v, has length [itex]|u||v| sin(\theta)[/itex] where [itex]\theta[/itex] is the angle between u and v? That happens to be the area of a parallelogram with sides u and v. The volume of a parallelopiped, with three intersecting sides given by a, b, c is equal to [itex]|a X b|\cdot c[/itex].
 
[I have no guess at all as to what "a= [-3,1]" could mean.]

it means lamda vector(the sign looks like summation)[-3;1]

[My first guess at your notation is that [2a,2,2], [4,1,a], and [2,2,a] are vectors with the direction and length of the concurrent sides of the parallelopiped. If that is what is meant, please say so! ]

ya,this is the meaning.

to find the volume, i use a(vector) . [b(vector) x c(vector) ]

but,the problem is the lamda which i don't know how to get the number to substitute in order to get the volume in integer form
 
somebody pls help
 
teng, we can't help if we don't know what the question is asking
 
teng125 said:
it means lamda vector(the sign looks like summation)[-3;1]

What?? If lambda is a vector, why does it only have two components? And what could "the sign looks like summation" mean?

You are still not making sense. Please go back to your book and copy the problem exactly as written. And if there is a variable like 'lambda' in the book which you don't know how to type, do not substitute 'a' for it in your post (which you have already used in two different places!), but use L or write out lambda. And differentiate between scalars and vectors.
 
  • #10
Teng125,
It would be worth your time, and ours, if you would learn to use our LaTex equation language.

https://www.physicsforums.com/showthread.php?t=8997"

You can simply click on any LaTex equation or symbol that apears in a post to see the code that generates it.
 
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  • #11
If three concurrent sides of the parallelpiped are given by
a=[2a,2 ,2] b=[4,1,a] c=[2,2,a] , then a ([itex]\lambda[/itex]) can't be a vector- you can't have vector as a component of another vector.

The "triple product" of three vectors is the determinant
[tex]\left| \begin{array}{ccc}x_0 & y_0 & z_0 \\ x_1 & y_1 & z_1 \\ x_2 & y_2 & z_2 \end{array} \right|[/tex]
and is equal to the product [itex]\vec{u} \cdot \vec{v} X \vec{w}[/itex]

In this case, that would be
[tex]\left| \begin{array}{ccc} 2\lambda & 2 & 2 \\ 4 & 1 & \lambda \\ 2 & 2 & \lambda \end{array} \right|[/tex]

I still don't understand what you mean by "a= [-3, 1]" since [itex]\lambda[/itex] must be a number, not a vector, and, anyway, a vector in this problem would have to have three components, not 2. Is it possible that you are asked to do this problem twice, once with [itex]\lamba= -3[/itex] and once with [itex]\lamba= 1[/itex]?
 

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