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## Homework Statement

What is the volume of a tank that is 8 ft in diameter and 15 feet high

## Homework Equations

## The Attempt at a Solution

Π x (4ft) 2 x 20ft

3.14 X 24ft x 15ft = 1130.4

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- Thread starter jim1174
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- #1

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What is the volume of a tank that is 8 ft in diameter and 15 feet high

Π x (4ft) 2 x 20ft

3.14 X 24ft x 15ft = 1130.4

Last edited:

- #2

SteamKing

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It's not clear where the figures 13.4 and 24 come from. Also, the word 'diameter' implies that the tank is a cylinder.## Homework Statement

What is the volume of a tank that is 8 ft in diameter and 15 feet high

## Homework Equations

## The Attempt at a Solution

13.4 X 24ft X 15ft= 1130.4

- #3

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h = height = 15 ft

A = cross-sectional area = to be determined

V = volume = to be determined

A = πD²/4

A = (3.14)(8 ft)²/4

A = 50.3 ft²

V = Ah

V = (50.3 ft²)(15 ft)

V = 754 ft³

- #4

SteamKing

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This looks good.

h = height = 15 ft

A = cross-sectional area = to be determined

V = volume = to be determined

A = πD²/4

A = (3.14)(8 ft)²/4

A = 50.3 ft²

V = Ah

V = (50.3 ft²)(15 ft)

V = 754 ft³

- #5

Ray Vickson

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I hope you realize that 3.14 is not the value of ##\pi##, but is just a 3-digit

h = height = 15 ft

A = cross-sectional area = to be determined

V = volume = to be determined

A = πD²/4

A = (3.14)(8 ft)²/4

A = 50.3 ft²

V = Ah

V = (50.3 ft²)(15 ft)

V = 754 ft³

- #6

Mark44

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Just to clarify your initial work, in your first expression above, you have 20 ft where it should have been 15 ft. I understand that "(4ft) 2" is supposed to be 4. The attempt at a solution

Π x (4ft) 2 x 20ft

3.14 X 24ft x 15ft = 1130.4

In your second expression you corrected the 20ft dimension, but 4 X 4 ##\neq## 24.

- #7

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D = diameter = 8 ft

h = height = 15 ft

A = cross-sectional area = to be determined

V = volume = to be determined

A = πD²/4

A = (3.14) (8 ft) ²/4

A = 50.24 ft²

V = Ah

V = (50.24 ft²) (15 ft)

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