- #1

- 79

- 0

## Homework Statement

What is the volume of a tank that is 8 ft in diameter and 15 feet high

## Homework Equations

## The Attempt at a Solution

Π x (4ft) 2 x 20ft

3.14 X 24ft x 15ft = 1130.4

Last edited:

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- #1

- 79

- 0

What is the volume of a tank that is 8 ft in diameter and 15 feet high

Π x (4ft) 2 x 20ft

3.14 X 24ft x 15ft = 1130.4

Last edited:

- #2

Staff Emeritus

Science Advisor

Homework Helper

- 12,810

- 1,669

## Homework Statement

What is the volume of a tank that is 8 ft in diameter and 15 feet high

## Homework Equations

## The Attempt at a Solution

13.4 X 24ft X 15ft= 1130.4

It's not clear where the figures 13.4 and 24 come from. Also, the word 'diameter' implies that the tank is a cylinder.

- #3

- 79

- 0

h = height = 15 ft

A = cross-sectional area = to be determined

V = volume = to be determined

A = πD²/4

A = (3.14)(8 ft)²/4

A = 50.3 ft²

V = Ah

V = (50.3 ft²)(15 ft)

V = 754 ft³

- #4

Staff Emeritus

Science Advisor

Homework Helper

- 12,810

- 1,669

This looks good.

h = height = 15 ft

A = cross-sectional area = to be determined

V = volume = to be determined

A = πD²/4

A = (3.14)(8 ft)²/4

A = 50.3 ft²

V = Ah

V = (50.3 ft²)(15 ft)

V = 754 ft³

- #5

Science Advisor

Homework Helper

Dearly Missed

- 10,704

- 1,721

h = height = 15 ft

A = cross-sectional area = to be determined

V = volume = to be determined

A = πD²/4

A = (3.14)(8 ft)²/4

A = 50.3 ft²

V = Ah

V = (50.3 ft²)(15 ft)

V = 754 ft³

I hope you realize that 3.14 is not the value of ##\pi##, but is just a 3-digit

- #6

Mentor

- 37,231

- 9,391

Just to clarify your initial work, in your first expression above, you have 20 ft where it should have been 15 ft. I understand that "(4ft) 2" is supposed to be 4. The attempt at a solution

Π x (4ft) 2 x 20ft

3.14 X 24ft x 15ft = 1130.4

In your second expression you corrected the 20ft dimension, but 4 X 4 ##\neq## 24.

- #7

- 79

- 0

D = diameter = 8 ft

h = height = 15 ft

A = cross-sectional area = to be determined

V = volume = to be determined

A = πD²/4

A = (3.14) (8 ft) ²/4

A = 50.24 ft²

V = Ah

V = (50.24 ft²) (15 ft)

Share:

- Replies
- 2

- Views
- 100

- Replies
- 6

- Views
- 834

- Replies
- 19

- Views
- 836

- Replies
- 30

- Views
- 2K

- Replies
- 12

- Views
- 597

- Replies
- 2

- Views
- 552

- Replies
- 10

- Views
- 276

- Replies
- 5

- Views
- 134

- Replies
- 17

- Views
- 686

- Replies
- 4

- Views
- 206