The discussion revolves around calculating the volume of a cylindrical tank with a diameter of 8 ft and a height of 15 ft. Participants are exploring the application of the volume formula for cylinders and addressing the implications of using approximations for π.
Several participants have provided calculations for the volume, with some expressing uncertainty about the values used for π and the dimensions. There is a recognition of the need for clarity in the initial expressions and an ongoing exploration of the correct approach to the problem.
Some participants note discrepancies in the calculations, particularly regarding the use of dimensions and the approximation of π. The discussion reflects a mix of correct and incorrect reasoning, with no clear consensus on the final volume calculation.
jim1174 said:Homework Statement
What is the volume of a tank that is 8 ft in diameter and 15 feet high
Homework Equations
The Attempt at a Solution
13.4 X 24ft X 15ft= 1130.4
This looks good.jim1174 said:D = diameter = 8 ft
h = height = 15 ft
A = cross-sectional area = to be determined
V = volume = to be determined
A = πD²/4
A = (3.14)(8 ft)²/4
A = 50.3 ft²
V = Ah
V = (50.3 ft²)(15 ft)
V = 754 ft³
jim1174 said:D = diameter = 8 ft
h = height = 15 ft
A = cross-sectional area = to be determined
V = volume = to be determined
A = πD²/4
A = (3.14)(8 ft)²/4
A = 50.3 ft²
V = Ah
V = (50.3 ft²)(15 ft)
V = 754 ft³
Just to clarify your initial work, in your first expression above, you have 20 ft where it should have been 15 ft. I understand that "(4ft) 2" is supposed to be 42, which can also be written as 4^2.jim1174 said:. The attempt at a solution
Π x (4ft) 2 x 20ft
3.14 X 24ft x 15ft = 1130.4