# What is the volume of a tank that is 8 ft in diameter and 15 ft high?

• jim1174

## Homework Statement

What is the volume of a tank that is 8 ft in diameter and 15 feet high

## The Attempt at a Solution

Π x (4ft) 2 x 20ft

3.14 X 24ft x 15ft = 1130.4

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## Homework Statement

What is the volume of a tank that is 8 ft in diameter and 15 feet high

## The Attempt at a Solution

13.4 X 24ft X 15ft= 1130.4

It's not clear where the figures 13.4 and 24 come from. Also, the word 'diameter' implies that the tank is a cylinder.

D = diameter = 8 ft
h = height = 15 ft
A = cross-sectional area = to be determined
V = volume = to be determined

A = πD²/4
A = (3.14)(8 ft)²/4
A = 50.3 ft²

V = Ah
V = (50.3 ft²)(15 ft)
V = 754 ft³

D = diameter = 8 ft
h = height = 15 ft
A = cross-sectional area = to be determined
V = volume = to be determined

A = πD²/4
A = (3.14)(8 ft)²/4
A = 50.3 ft²

V = Ah
V = (50.3 ft²)(15 ft)
V = 754 ft³
This looks good.

D = diameter = 8 ft
h = height = 15 ft
A = cross-sectional area = to be determined
V = volume = to be determined

A = πD²/4
A = (3.14)(8 ft)²/4
A = 50.3 ft²

V = Ah
V = (50.3 ft²)(15 ft)
V = 754 ft³

I hope you realize that 3.14 is not the value of ##\pi##, but is just a 3-digit approximation to the true value (and which is sometimes close enough in some problems, but not nearly accurate enough in some other cases).

. The attempt at a solution
Π x (4ft) 2 x 20ft

3.14 X 24ft x 15ft = 1130.4
Just to clarify your initial work, in your first expression above, you have 20 ft where it should have been 15 ft. I understand that "(4ft) 2" is supposed to be 42, which can also be written as 4^2.

In your second expression you corrected the 20ft dimension, but 4 X 4 ##\neq## 24.

ok i think i got it

D = diameter = 8 ft
h = height = 15 ft
A = cross-sectional area = to be determined
V = volume = to be determined

A = πD²/4
A = (3.14) (8 ft) ²/4
A = 50.24 ft²

V = Ah
V = (50.24 ft²) (15 ft)
Volume V = 753.6 ft³

Final Answer is = V = 753.6 ft³