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## Homework Statement

A proton orbits a long charged wire, making 1.60 * 10^6 revolutions per second. The radius of the orbit is 1.60 cm. What is the wire's linear charge density?

## Homework Equations

F=qE

F=ma

F=(mw^2)/r

F=Eklambda/2r=mw^2/r (the radiuses cancel out)

## The Attempt at a Solution

a=w^2/r=((1.60*10^6 rev/s *2pi)^2/.016 m

F=ma m=1/67 *10^-27

E=F/q E=6.59*10^7

F=Eklambda/2r=mw^2/r (the radiuses cancel out)

LAMBDA=5.7*10^-4 nC/m This is incorrect. Where am I going wrong? I have stared at this problem too long and can't figure out what the problem is (it might be some minute conversion issue or something because I think the set up is correct)?