What is the work done by weight on a crate being pushed up an inclined surface?

Click For Summary
SUMMARY

The work done by the weight on a 300 kg crate pushed up a 30-degree incline with a horizontal force of 2400 N is calculated using the formula for work done (WD = F.d). The relevant force is the gravitational force acting on the crate, which is mg, where g is the acceleration due to gravity. The work done by the weight is determined by the vertical displacement of the crate along the incline, simplifying the problem significantly by focusing solely on the gravitational force.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concept of work and energy
  • Knowledge of trigonometric functions related to inclined planes
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of gravitational potential energy and its relation to work done
  • Learn about the components of forces on inclined planes
  • Explore the implications of friction on work done in similar scenarios
  • Investigate the relationship between force, mass, and acceleration in detail
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of work done in inclined planes.

shaunanana
Messages
3
Reaction score
0

Homework Statement



a 300 kg crate is on a rough surface inclined at 30 degrees. A constant force P=2400 N is applied horizontally to the crate. The force pushes the crate a distance of 3.0 m up the incline, in a time interval of 9.0 s, and the velocity changes from v1=0.7 m/s and v2=2.9 m/s. What is the work done by the weight?


Homework Equations



WD=F.d

The Attempt at a Solution


i have found the parallel components:
Fnet=Psin(theta) -mgsin(theta)
Psin(theta)-mgsin(theta)=ma
and the perpendicular components:
Fnet=Fn-mg
Fn=mg
I'm not 100% sure any of this is correct, and now I don't know where to go with it
 
Physics news on Phys.org
Welcome to PF!

Hi shaunanana! Welcome to PF! :smile:

(have a theta: θ and try using the X2 tag just above the Reply box :wink:)

You're only asked for the work done by the weight (the mg force), so most of the information in the question is unnecessary.

And work done = force "dot" distance.

So work done by the weight = … ? :smile:​
 
Oh wow, that's so simple...maybe I should stop trying to do my homework so late at night!

Thank you! :)
 

Similar threads

Questions Regarding a Cat Going Up a Ramp
  • · Replies 56 ·
2
Replies
56
Views
5K
What is the Change in Kinetic Energy of a Crate Being Pulled at an Angle?
  • · Replies 1 ·
Replies
1
Views
2K
Determine the work done by the force due to gravity
  • · Replies 14 ·
Replies
14
Views
3K
What is the change in kinetic energy of the crate pulled up a rough incline?
  • · Replies 6 ·
Replies
6
Views
3K
Crate pushed up an inclined plane
  • · Replies 6 ·
Replies
6
Views
6K
Work done by the force of a man on a crate of 80N
  • · Replies 14 ·
Replies
14
Views
6K
Kinetic Energy and Work/ Work depends on acceleration?
  • · Replies 3 ·
Replies
3
Views
3K
Finding Work Done by Gravity on Inclined Crate
  • · Replies 6 ·
Replies
6
Views
17K
Work done by man pushing a crate up a ramp, includin done on
  • · Replies 5 ·
Replies
5
Views
11K
How Long Until a Crate Reaches a Specific Velocity on an Incline?
  • · Replies 17 ·
Replies
17
Views
4K