The problem involves calculating the work required to stretch a spring with a given spring constant from its equilibrium position. The original poster states the spring is initially stretched 0.21 m and seeks to find the work needed to stretch it an additional 0.14 m.
Some participants have attempted calculations and shared their results, while others have pointed out potential errors in the approach. There is an ongoing exploration of the correct interpretation of the problem and the calculations involved, with no explicit consensus reached.
There is a noted typo in the distance value used in the calculations, leading to further questioning about the correct values to apply. Participants are also considering the implications of the work being negative and the area under the force-distance curve.
blayman5 said:Homework Statement
A spring with spring constant of 29 N/m is
stretched 0.21mfromits equilibrium position.
How much work must be done to stretch it
an additional 0.14 m? Answer in units of J.
Homework Equations
W=-kx(x)/2
The Attempt at a Solution
I solved it and got 0.4263 and it was wrong. does it need to be negative?
blayman5 said:i did ((29)(0.21)(0.14))/2 =0.4263. does it need to be negative?
blayman5 said:Ok so that means it would equal
29*(.21+14)2/2 - 29*(.21)2/2 =1.1368
Thanks
LowlyPion said:That's not quite right.
Additional work = Difference in work = 29*(.21+14)2/2 - 29*(.21)2/2
dleccord said:wait...
wait wait... why is it 14 instead of .14?