What is wrong with this equation ?

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The discussion centers on the dynamics of a system involving two blocks (m1 = 2.00 kg and m2 = 6.00 kg) connected by a massless string over a solid disk pulley (radius R = 0.250 m, mass M = 10.0 kg) on a fixed wedge inclined at an angle of 30.0°. The equation presented for the system's acceleration neglects the moment of inertia of the pulley, which is critical for accurate calculations. The correct approach requires incorporating the pulley’s rotational dynamics to determine both the acceleration of the blocks and the tensions in the string.

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A block of mass m1 ϭ 2.00 kg and a block of mass
m 2 ϭ 6.00 kg are connected by a massless string over a pul-
ley in the shape of a solid disk having radius R ϭ 0.250 m
and mass M ϭ 10.0 kg. These blocks are allowed to move
on a fixed block-wedge of angle ␪ ϭ 30.0° as in Figure
P10.37. The coefficient of kinetic friction is 0.360 for both
blocks. Draw free-body diagrams of both blocks and of the
pulley. Determine (a) the acceleration of the two blocks
and (b) the tensions in the string on both sides of the
pulley.

[PLAIN]http://img820.imageshack.us/img820/9199/36360522.jpg

(m1 + m2)a = m2gSin30 - [tex]\mu[/tex]m1g - [tex]\mu[/tex]m2gcos30

what is wrong with this equation ?
 
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ManishR said:
what is wrong with this equation ?

You neglect the momentum of inertia of the pulley.
 

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