What levels result from a 4F term

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The discussion revolves around determining the energy levels resulting from a 4F term in atomic physics. The user correctly identifies that the "F" indicates L = 3, leading to seven possible magnetic quantum numbers (ml = -3 to 3). However, clarification is sought on the significance of the "4" in 4F, which typically denotes the multiplicity of the term. The conversation emphasizes the importance of understanding both the total angular momentum and the multiplicity in calculating the states associated with the term. Overall, the user is looking for guidance on the correct approach to solving the problem related to the 4F term levels.
physicisttobe
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Hi everyone!

I can't solve a problem. It is about the following task. How exactly should I proceed here?

Task A): What levels result from a 4F term? How many states are there at each level?

I tried many ways but none of them helped me to solve this problem.
However, I have some basic ideas: We have a F term, this means l=3, ml= -3,-2,-1,0,1,2,3. In sum we have 7 levels.
Is this reasoning correct or am I on the wrong track? I would welcome your response, thanks in advance.

(And I would like to apologize for my English skills because I come from a non-English speaking country.)
 
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I assume you are using spectroscopic notation. You have correctly indicated that the "F" signifies L = 3.
What does the "4" in 4F signify?
 
Thread 'Chain falling out of a horizontal tube onto a table'

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
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