What Mistakes Did I Make in Calculating Mars Physics Problems?

  • Thread starter Thread starter dabouncerx24
  • Start date Start date
  • Tags Tags
    Physics
Click For Summary
The discussion centers on identifying mistakes in calculating physics problems related to the Sojourner rover on Mars. The user correctly applied gravitational formulas for calculating Mars' gravity, Sojourner's weight, and the normal force on an inclined ramp. However, they struggled with understanding the net force at constant velocity, concluding there is no net force, which is accurate but overlooks opposing forces. For the maximum distance the rover can travel, the user needs to consider the power required to overcome friction or other resistances, emphasizing the importance of understanding energy usage in relation to power. Overall, the calculations for parts A-D are on the right track, but further clarification is needed for part E regarding energy and power dynamics.
dabouncerx24
Messages
11
Reaction score
0
Hi, I need a little help on a problem I did. I've most of the solutions but I think they're all wrong, can someone help me point out what I did wrong?

Here is the problem:

The Sojourner rover vehicle was used to explore the surface of Mars in 1997.
Here is some info to aid solving the below problems:

Mars data: Radius = 0.53 x Earth's R Mass = 0.11 x Earth's mass
Sojourner data: Mass = 11.5 kg Wheel diameter = 0.13 m Stored energy available: 5.4 x 10^5 J Power required for driving under avg. conditions: 10W
Land speed: 6.7 x 10^-3 m/s

a. Determine the acceleration due to gravity at the surface of Mars in terms of g, the acceleration due to gravity at the surface of Earth.

For a, I just used the same method that calculates the Earth's acceleration of gravity. I used:

g = G (m/r^2), with m and r being Mars' of course.
so it would be g = 6.67x10^-11 (6.567x10^23 / 1.1434x10^13), which gave me 3.05 m/s^2.

B. Calculate Sojourners weight on Mars.
I just used the W=mg concept. Sojourner is 11.5 kg and Mars' g is 3.05, so multiple and it = 35.13 N.

C. Assume that the vehicle is rolling down a ramp inclined at 20 degress to the horizontal. The ramp must be lightweight but strong enough to support the vehicle. Calculate minimum NORMAL force that must be supplied by the ramp.

What I did was I used the normal force equation.

so I got Normal F=mgcostheta = 11.5(3.05)(cos 20) = 32.96 N.

D. What is the net force on the vehicle as it travels across the Martian surface at constant velocity?

I kinda got stuck on this one so I made a guess. Since it is constant v, there is no acceleration. So according to the net force equation, F=ma, it becomes F=m(0), so there is no net force.

E. Determine the max distance that the vehicle can travel on a horizontal Martian surface using its stored energy.

I got completely stuck on this one, didn't do anyting for it.





Any help will be appreciated, thank you!
 
Physics news on Phys.org
dabouncerx24 said:
Stored energy available: 5.4 x 10^5 J Power required for driving under avg. conditions: 10W
Land speed: 6.7 x 10^-3 m/s


E. Determine the max distance that the vehicle can travel on a horizontal Martian surface using its stored energy.

I got completely stuck on this one, didn't do anyting for it.





Any help will be appreciated, thank you!

I did not check your arithmetic, but your approach is correct for A-D. For E you have to use the information you were given in the probleam about power needed under "average" conditions. This means there is some force opposing the motion at all times. It could be due to a layer of sand or rolling friction. It does not matter what the source is. You just know that steady power has to be applied to keep the rover moving. Power is the rate of using energy, and your energy supply is limited.
 
For A, express mars' gravitation in terms of the Earths. aka

g_{mars} = \left(\frac{g_{mars}}{g_{earth}}\right) g_{earth} where the quantity in brackest is numerical and the rest are just units.
 

Similar threads

Replies
2
Views
6K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
5
Views
833
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
4K