What Potential Difference Is Needed to Stop an Electron?

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SUMMARY

The discussion centers on calculating the potential difference required to stop an electron with an initial speed of 4.2 x 105 m/s. The relevant equations include work-energy principles, specifically W = ΔK and W = qΔV. The user correctly identifies that the potential difference should be negative due to the negative charge of the electron, yet encounters a positive result for ΔV. The confusion arises from the sign conventions in the equations used, particularly regarding the kinetic energy change and charge of the electron.

PREREQUISITES
  • Understanding of kinetic energy and its relationship to work (W = ΔK).
  • Familiarity with electric charge, specifically the charge of an electron (Q = -1.60 x 10-19 C).
  • Knowledge of potential difference and its role in electric fields.
  • Basic algebra skills for manipulating equations.
NEXT STEPS
  • Review the work-energy theorem and its application in electric fields.
  • Study the concept of electric potential and potential difference in detail.
  • Learn about the implications of charge signs in physics equations.
  • Explore examples of stopping charged particles in electric fields.
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism and energy concepts, as well as educators looking for examples of work-energy principles applied to charged particles.

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Homework Statement


What potential difference is needed to stop an electron having an initial speed of 4.2*10^5 m/s?


Homework Equations


W = delta K
W = q*delta V


The Attempt at a Solution


So I'm pretty sure that the potential difference should be negative in order to stop the electron, but I keep getting a positive answer (the correct magnitude, but incorrect sign).

I set delta K = q*delta V.

I know delta K will be less than zero since K(final) < K(initial) and q should also be negative since we're dealing with an electron. But this gives me a positive delta V.

Where am I going wrong?

Thanks in advance.
 
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so you have 1/2 mv2=VQ

for an electron Q=-1.60*10-19C
 

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