What Resources Can Help You Understand Emission Spectra?

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    Emission Spectra
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Emission spectra involve the light emitted by elements when their electrons transition between energy states, resulting in various colors and frequencies. Resources for understanding this topic include textbooks on atomic physics, online educational platforms, and scientific articles that explain the principles behind emission spectra and their applications. A spectrometer can be used to analyze the emitted light and identify elements based on their unique spectral lines. Practical examples, such as the bright yellow color of sodium when heated, illustrate these concepts effectively. Understanding emission spectra is crucial for applications in chemistry and physics, particularly in identifying elements and compounds.
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I don't really have a HW question, I am doing physics independent study and I have to do a project. My teacher suggested doing it about emission spectra, only, I have no idea what that is and searching EBSCO is not being really helpful, does anyone have any resources, ideas, etc where I could learn more about it?

Thanks!

Also, I'm sorry if this is in the wrong section -_-'...

 
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elephantorz said:
I don't really have a HW question, I am doing physics independent study and I have to do a project. My teacher suggested doing it about emission spectra, only, I have no idea what that is and searching EBSCO is not being really helpful, does anyone have any resources, ideas, etc where I could learn more about it?

Thanks!

Also, I'm sorry if this is in the wrong section -_-'...


I just asked my bf [math majors for the win] and does it have to do with light being emitted by different elements? Neon lights? Hmmm...
 
Atoms have many possible energy states for electrons to be in. There can be many possible combinations for electrons to drop from higher to lower states, for example, dropping from principal quantum number n=7 to n=3, etc. Each possible combination is a different change in energy, so the photons given off have that variety of energy values. The frequency of a photon is proportional to its energy, so you can get many colors. You can put the light through a spectrometer to see the individual colors, then identify what the element is. This procedure refers to gases, where atoms are individual things with little effect on each other. You can hold a sample of a solid in a flame and it will emit some hot vapor and a characteristic color. A well-known example is "sodium yellow", a bright color of a specific frequency associated with sodium, which you can produce by heating some sodium chloride.
 
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Thanks!
 
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The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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