What Speed Keeps the Cylinder Stationary in the Puck-Cylinder System?

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Homework Help Overview

The problem involves a puck sliding in a circular motion on a frictionless table, connected to a hanging cylinder by a cord. The objective is to determine the speed that keeps the cylinder stationary while considering the forces acting on both the puck and the cylinder.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to analyze the forces acting on both the puck and the cylinder, deducing relationships between tension and gravitational force. Some participants suggest ensuring clarity between the two different masses involved in the problem.

Discussion Status

The discussion reflects an exploration of the relationships between forces and the roles of different masses. Guidance has been offered regarding the need to distinguish between the two masses in the equations, which may help clarify the original poster's misunderstanding.

Contextual Notes

Participants note the importance of correctly applying the equations for centripetal force and gravitational force, as well as the implications of having two distinct masses in the system.

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Homework Statement


A puck of mass m = 1.10 kg slides in a circle of radius r = 18.0 cm on a frictionless table while attached to a hanging cylinder of mass M = 3.00 kg by a cord through a hole in the table. What speed (in m/s) keeps the cylinder at rest?

Homework Equations


F = ma

The Attempt at a Solution


I know the Fnet,y for the hanging cylinder is zero because it does not move, so I deduced that T - Fg = 0.
On the puck the 2 things I looked at was the a moving towards the hole and the tension which I am also deducing is moving towards the hole, away from the puck. (Note: I left out FN and Fg because I didn't see how they would apply in the equation for the puck.) I thus got the equation T = ma.

I then plugged in the in this T into the previous equation to get: ma - Fg = 0
I then simplified the equation to a = g. Knowing that a in circular motion with constant velocity is a = v2/R, so the equation I ended up with was v = √Rg. This came out to 1.328 ms-1, which is wrong. Could somebody tell me where my thinking went astray and how I can fix this.
 
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There are TWO different masses, so you need to keep two different m's in your equation or replace them with the two different numbers. Your solution will be more elegant if you write Fc = Fg first (centripetal force is provided by the gravitational force), then replace them both with their detailed formulas.
 
Thank you very much. I overlooked that there were two different masses involved in the equation and just worked them out of my problem by mistake.
 
Most welcome! It is a pleasure to save you the frustration of a tiny mistake after you demonstrate your mastery of the whole problem.
 

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