What Steps Are Needed to Solve This Complex Pulley Problem?

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Homework Help Overview

The discussion revolves around a complex pulley problem involving multiple pulleys and a single string, with participants attempting to understand the mechanics involved. The original poster expresses difficulty in solving the problem and mentions specific constraints regarding the diagram provided.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for clarity in the diagram and the importance of labeling forces and ropes. Questions about the fixed nature of pulleys and the implications of gravity are raised. Some suggest using mathematical relationships between the distances of the ropes and differentiating them to find solutions.

Discussion Status

The discussion is ongoing, with participants providing guidance on how to approach the problem and emphasizing the need for the original poster to clarify their diagram and assumptions. There is no explicit consensus on a solution yet, but various methods and considerations are being explored.

Contextual Notes

There are constraints mentioned regarding the original poster's ability to edit or provide a clearer diagram, as well as the requirement for attachment approval before further discussion can take place.

a_d777
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Awesome pulley problem!

Hey, i just came across this pulley problem and thought it was easy to solve...on solving, my answers were not matching...!

Check the attachment...

There is a single string. Ignore the friction.
The mass of the pulleys A, B & C is 1 Kg each.
*ignore the dirty, bad diagram...what else can i do in windows!?*


also post the method of doing...

correct options are a,b & d...
 

Attachments

  • phy.JPG
    phy.JPG
    17.7 KB · Views: 412
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No fair! Misleading title! I'm going to complain to the Mentors!
I came here expecting something about a chicken cannon.

Seriously, though, welcome to PF. Nothing can be done until your attachment is approved.
 
Your diagram is excellent- just enlarge it. Note that we do require that you show what you have tried yourself and you must try. To get you started, I would recommend you lable the ropes between pulleys (and the forces for each), say x,y,z,u,v,w. I count 6such ropes and so 6 such forces.
 
Correction. Nothing can be done by non-Mentors, who can't see the attachments until they're approved. :-p
 
hm...

ok, but...
hm...
well, i can't work on my PC so well ...
i mean i can't do high-end editing...Bad in computers...!
i can't even scan the page of my notebook because i don't have a scanner!

well, i will surely post what I've tried...veryy soon...!
and, sorry...
its pulleY...
not pulleT
!
 
:biggrin:.[/color]
 
Is C fixed?

Have a think as to which are fixed, and (for the start) draw arrows on the diagram indicating which way the string will go.
 
Danger said:
No fair! Misleading title! I'm going to complain to the Mentors!
I came here expecting something about a chicken cannon.
Yeah, you beat me to it.
 
s/pullet/pulley/

- Warren
 
  • #10
i really [tex]don't[/tex] want to sound stupid but please do attach some points to the cieling(if any) otherwise the system will fall don due to gravity(if any )


anyways just use the fact that in a closed rigid system the tension(internal force) does no work.
since tension on each pulley is known spped hence accelaration of each pulley is known
 
  • #11
There's an easy way for solving pulley problems, but I really don't know how to use that method.

make an equation using all ropes distances(find relationships between them), and differentiate them.
anyone knows that method?
 
  • #12
yes the constrain t method but that's just mathematical representation of what u think intutively
for example consider the standard pulley problem of two masses say [tex]m_{1}[/tex] and [tex]m_{2}[/tex] hanging on two ends.
now say one get's down by [tex]x[/tex] other by [tex]y[/tex] then since rope length is constsnt we have
[tex]x+y=0[/tex]
differentiating
[tex]\frac{dx}{dt} + \frac{dy}{dt}=0[/tex]
thus [tex]v_{m_{1}}=-v_{m_{2}}[/tex]
differentiating again
[tex]a_{m_{1}}=-a_{m_{2}}[/tex]
 
  • #13
I can't do that with more than two pulleys ><
 
  • #14
chroot said:
s/pullet/pulley/

You rat! Now my post just looks stupid. :frown:
I'm glad that Dave was a witness to the original title. :-p
 
  • #15
rootX said:
I can't do that with more than two pulleys ><

what is that u couldn't solve
 
  • #16
hey, isn't there things like photoshop and paint? they are good programs that can help you to edit your pictures. try them! =)
 
  • #17
Um...correction...!

sorry for the wrong image...well, not wrong...but incomplete...!
The motion of pulleys or strings is not mentioned in the question...
 

Attachments

  • phy.JPG
    phy.JPG
    17.7 KB · Views: 362
Last edited:

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