# What to take as p(x,y) and q(x,y) with partials

1. Oct 3, 2006

2. Oct 4, 2006

### Fermat

Your DE is P(x,y)dx + Q(x,y)dy = 0 and you want to find out if it is exact.

The equation will be exact if $$\frac{\partial P}{\partial y} = \frac{\partial Q}{\partial x}$$.

You have P(x,y) = 5x + 4y giving $$\frac{\partial P}{\partial y}=4$$

And Q(x,y) = 4x - 8y² giving $$\frac{\partial Q}{\partial x} = 4$$

Have a look at this site and see if it helps.

3. Oct 4, 2006

### prace

Great, I took a quick glance at the sight and it looks as if that will help a lot. I will have to take a deeper look into it later this afternoon, but I just wanted to say thanks for your imput. I'll let you know if I have any more problems. =p

thanks!! ^_^