What Units Should Be Used for the Left Half of the GR Equation?

  • Context: Graduate 
  • Thread starter Thread starter snoopies622
  • Start date Start date
  • Tags Tags
    Einstein Tensor
Click For Summary

Discussion Overview

The discussion centers on the appropriate units for the left half of the General Relativity (GR) equation, exploring what is being quantified and how it relates to the right-hand side involving the stress-energy tensor.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant questions the appropriate units for the left half of the GR equation, suggesting possibilities like meters or square meters.
  • Another participant asserts that the left side should have the same units as the right side, specifically \(\kappa T^{\mu\nu}\).
  • A different participant claims that the left side represents a measurement of curvature, proposing units of \(m^{-2}\).
  • One participant acknowledges the previous answer as satisfactory.
  • Another participant suggests that a previous contributor may have intended to encourage independent discovery of the answer.
  • It is noted that the claim about curvature assumes the use of geometric units, which are common but not universally applied.
  • A later reply confirms that the units are SI-consistent if the stress-energy tensor \(T\) is measured in \(J/m³\).

Areas of Agreement / Disagreement

Participants express differing views on the appropriate units and the assumptions underlying those units, indicating that multiple competing perspectives remain without a clear consensus.

Contextual Notes

The discussion includes assumptions about the use of geometric units and the conditions under which the units are considered SI-consistent, which may not be universally accepted.

snoopies622
Messages
852
Reaction score
29
What are the appropriate units for the left half of the GR equation? Meters? square meters..? To put it another way, what exactly is being quantified?
 
Physics news on Phys.org
The same as the right hand side, [tex]\kappa T^{\mu\nu}[/tex]
 
It's a measurement of curvature, in [tex]m^{-2}[/tex].
 
Thanks, Ich. That's the answer I was looking for.
 
I guess Mentz114 just wanted to motivate you to find it out yourself. It's not difficult.
 
Note that Ich's answer assumes that geometric units are being used, which is very common, but perhaps not quite universal.
 
Note that Ich's answer assumes that geometric units are being used, which is very common, but perhaps not quite universal.
I double-checked and found the units to be SI-consistent, as long as T is measured in J/m³.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 186 ·
7
Replies
186
Views
13K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K