What values of x make the function f(x) = sin(sqrt(x)) defined?

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The function f(x) = sin(sqrt(x)) is defined when the argument of the square root, x, is non-negative, meaning x must be greater than or equal to 0. The sine function, sin(t), is defined for all real numbers, so the primary concern is ensuring that the square root is valid. Therefore, the values of x that make the function defined are x ≥ 0. There was some confusion regarding the intervals discussed, particularly with incorrect implications about negative values. Ultimately, the key takeaway is that f(x) is defined for all x in the range [0, ∞).
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i need to find for what values X is defined in the given function

i found for the sin part and for the the square root but i don't know how to combine them
into a final answer:
http://img168.imageshack.us/img168/1434/39293849jq8.gif
 
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transgalactic said:
i need to find for what values X is defined in the given function

i found for the sin part and for the the square root but i don't know how to combine them
into a final answer:
http://img168.imageshack.us/img168/1434/39293849jq8.gif
I'm afraid that I do not agree with your interval for t.
 
Last edited by a moderator:
Among other things you have written
\pi+ 2k\pi\le t\le 0+ 2k\pi
which implies that \pi is negative!

sin(t) is defined for ALL t. sin(\sqrt{x}) is defined as long as \sqrt{x} is.
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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