What values of x make the function f(x) = sin(sqrt(x)) defined?

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SUMMARY

The function f(x) = sin(sqrt(x)) is defined for all values of x that make sqrt(x) a real number. This means x must be greater than or equal to 0, as the square root function is only defined for non-negative values. The sine function, sin(t), is defined for all real numbers t, thus the only restriction on f(x) comes from the square root component. Therefore, the function f(x) is defined for x in the interval [0, ∞).

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transgalactic
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i need to find for what values X is defined in the given function

i found for the sin part and for the the square root but i don't know how to combine them
into a final answer:
http://img168.imageshack.us/img168/1434/39293849jq8.gif
 
Last edited by a moderator:
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transgalactic said:
i need to find for what values X is defined in the given function

i found for the sin part and for the the square root but i don't know how to combine them
into a final answer:
http://img168.imageshack.us/img168/1434/39293849jq8.gif
I'm afraid that I do not agree with your interval for t.
 
Last edited by a moderator:
Among other things you have written
[tex]\pi+ 2k\pi\le t\le 0+ 2k\pi[/tex]
which implies that [itex]\pi[/itex] is negative!

sin(t) is defined for ALL t. [itex]sin(\sqrt{x})[/itex] is defined as long as [itex]\sqrt{x}[/itex] is.
 
Last edited by a moderator:

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