What were Jack and Jill's velocities on the hill?

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SUMMARY

Jack and Jill's velocities on the hill were analyzed with Jack running at 3.6 m/s and Jill having a horizontal velocity component of 2.3 m/s. To determine the angle of the hill and Jill's vertical velocity component, a right triangle was constructed using these velocities. The angle can be calculated using trigonometric functions, specifically the tangent function, while the vertical component can be derived using the sine function. This approach provides a clear method for solving the problem using basic trigonometry.

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Homework Statement


Jack and Jill ran up the hill at 3.6 m/s. The horizontal component of Jill's velocity vector was 2.3 m/s.

(a) What was the angle of the hill?


(b) What was the vertical component of Jill's velocity?


Homework Equations



?


The Attempt at a Solution


I don't know where to start
 
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Think of a triangle.
Jill has moved horizontally at 2.3m/s so draw a horizontal line 2.3 units long
she moves up the slope at 3.6m/s so draw the slope of the triangle 3.6 units long.

Then all you need to find is the angle and the length of the third side.
You can use trig for this, but you can get a good estimate from your drawing.
 
thanks! that helped a lot!
 

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