What were my mistakes in solving this ladder problem in physics?

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SUMMARY

The discussion centers on the miscalculation of the normal force in a physics ladder problem. The user incorrectly defined the normal force as Fn=Ffriction instead of using the correct formula Fnormal = ((mg1d1) + (m2gd2)) / d3. The values substituted into the equation were ((400 x 2) + (100 x 5cos60)) / 10sin60, leading to an incorrect result of 121.243 N. The user is advised to clarify variable definitions and ensure the correct axis is chosen for torque summation.

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Homework Statement
A 400N woman climbs a 100N, 10m ladder inclined at an angle of Θ = 60°. When she is 3m away from the wall, how much friction is needed at point A to keep the ladder from slipping. (Assume theres no friction between wall and ladder.) (Answer 342N)
Relevant Equations
Fground = mg + mdg
Fn = Ffriction
Torque = Fn(d3) -mg(d2) - m2g(d1)
I set up all my summations and ended with Fnormal = ((mg1d1) + (m2gd2)) / d3. The values I put in were ((400 x 2) + (100 x 5cos60)) / 10sin60.
I got 121.243 N as my answer but that is incorrect. What did I do wrong?
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Please define all your variables (d, d1, d2, d3, m, m2, Fn) and specify your choice of axis for torque summation.
(Fn sounds like it should be normal force, but you wrote Fn=Ffriction.)
 

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