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So what equation do you get by carrying out the differentiation in post #16?Adesh said:Accelerations of block A and block B.
So what equation do you get by carrying out the differentiation in post #16?Adesh said:Accelerations of block A and block B.
Another way to look at this problem:Adesh said:...
Please explain me as I have no reason to believe that block A and B will have same acceleration.
Acceleration of the blocks.haruspex said:So what equation do you get by carrying out the differentiation in post #16?
But there is something that is troubling me, ##(-l_1, 0)## is the current position of the block A and ##(0, -l_2)## is the current position of block B, but acceleration is not the second derivative of fixed positions (because in that case it will always come out to be zero). We should say, that at ##t=0## the positions of the blocks were so and so.haruspex said:So what equation do you get by carrying out the differentiation in post #16?
You did not define l1 etc. as merely initial positions. Why should they not mean positions at time t, i.e. define l1 = l1(t) etc.Adesh said:But there is something that is troubling me, ##(-l_1, 0)## is the current position of the block A and ##(0, -l_2)## is the current position of block B, but acceleration is not the second derivative of fixed positions (because in that case it will always come out to be zero). We should say, that at ##t=0## the positions of the blocks were so and so.
Yes, this advice and way of solving it is helping me very much. Now, I’m able to solve almost all problems of pulleys and strings, credit goes to you.haruspex said:You did not define l1 etc. as merely initial positions. Why should they not mean positions at time t, i.e. define l1 = l1(t) etc.
Also, you don't need to use vector representations. Just define each displacement in the direction that suits it.