- #1

- 741

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[tex]\frac {v - v_c}{cr} = \frac {dv_c}{dt}[/tex]

Suppose I integrate this so as to get the original function...apparently the original function seems v

_{c}...so I should get this function after integrating; since we have dt in the denominator, it means the original function v

_{c}was differentiated WRT t...so I gotta integrate it WRT t to get v

_{c}.

Am I right till now?

But there's no t towards the LHS...is there anyway to integrate this...I mean I'm confused with this part...what should be done?