1 of 2: What would an Ideal Volt Meter read if an Ideal Capacitor had a charge difference of... 6.25 quintillion electrons (6.25 X 10 to the 18th) between its two plates? In other words... if there were 6.25 x 10^18th extra electrons on one plate... and you connected an Ideal Volt Meter between the two plates. An Ideal Volt Meter would have an infinate input impedance so it would allow no current to flow through it and therefore would not distort the measurment by allowing charge to flow from one plate of the capacitor to the other. An Ideal Capacitor would have a perfect dialectric and no current leakage would occur between the two plates so the charge difference would remain constant until such time as the capacitor were discharged through some sort of conductor. 2 of 2: What would the charge difference be in electrons for the volt meter to measure one volt? thanks for any help on this.