What would the angle φ be for this deflected laser beam?

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Homework Help Overview

The problem involves a mirror deflecting a horizontal laser beam by a specified angle θ, with the goal of determining the angle φ. The context is rooted in the principles of reflection and geometry.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the angles of incidence and reflection, with some suggesting the use of geometric principles to derive the necessary relationships. Others question the need for normals and propose alternative methods for visualizing the problem.

Discussion Status

There is an ongoing exploration of the geometric relationships involved in the problem, with various participants offering insights and references to relevant concepts. Some guidance has been provided regarding the angles, but no consensus has been reached on the approach to take.

Contextual Notes

Some participants note the importance of understanding basic geometry principles, while others highlight the distinction between reflection and refraction, indicating potential confusion in the problem setup.

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Homework Statement


The mirror in the image below deflects a horizontal laser by angle θ. What is the angle φ if θ = 60°.
5.jpg


Homework Equations


θir

The Attempt at a Solution


So I know that, if I draw a line normal to the mirror, that will make it so that the incident angle and the reflected angle equal 60° (since 180-60=120 and the 2 angles have to be the same, so 120/2=60) but after that, I have no idea what to do. I know the angle is 30°, but how did they get that angle. Maybe I just need to reviw my geometry.
 
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Draw the normal to the mirror and identify the angle of incidence and the angle of reflection.
[Edit] ... also derive the equation rrlating the angles first, then plugbin the numbers

Take care with notation.
 
Last edited:
Yes, you'll get nowhere without your junior high geometry. Relationships expressed concisely as "co-interior angles are supplementary", or maybe use "alternate angles are equal".
 
We don’t need no stinkin’ normals. (See note below.) All we need is a suitable diagram…
diag.jpg

This immediately shows that θ = 2Φ.

I think I've told you too much. But can you explain why the marked angles in the diagram are equal to Φ?

Note.
To understand the opening sentence, you would need already to be familiar with the original reference. (Replace ‘normals’ by ‘badges’ and do a search, if you have nothing better to do!)
 
This is an ancient thread ... just pointing this out since the OP last logged in about a year ago.
 
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yes it has to do with reflection angles:
E=180
P vertical=90
and we have 60 degree
The unknown angle is = 180 - 90 - 60 = 30 degrees
 
jim mcnamara said:
This is an ancient thread ... just pointing this out since the OP last logged in about a year ago.
I would call it a zombie thread. 🧟‍♂️ Once revived, it acquires a strange life of its own. Only mentors possesses the awesome powers to kill it for good. Hint, hint.
 
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