What's Going On When Iron Electrodes Are Electrolyzed in Sodium Hydroxide?

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The discussion centers on the electrolysis of a concentrated sodium hydroxide solution using iron electrodes. The expected reactions at the positive electrode include the oxidation of water to oxygen and the oxidation of iron to iron ions, while the negative electrode primarily produces hydrogen gas from water. Despite the theoretical predictions suggesting that iron should oxidize due to its lower standard electrode potential, the experiment yields oxygen and hydrogen without any formation of iron hydroxide. This outcome raises questions about the actual reaction dynamics, emphasizing that reactions occur preferentially based on their thermodynamic favorability. The presence of water and its tendency to react may overshadow the oxidation of iron, leading to the observed results. The discussion highlights the complexity of electrochemical reactions and the influence of various factors on the expected outcomes.
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I've got a question that is bugging me

If I have a concentrated sodium hydroxide solution and electrolyze it with iron electrodes, some of the possible reactions at the positive electrode are
2H2O -> O2 + 4H++4e-. Eo = -1.23 V
4OH- -> O2 + 2H2O + 4e-. Eo = -0.40 V
Fe -> Fe2+ + 2e-. Eo = 0.44 V

and at the negative electrode, the most likely reaction is
2H2O +2e- -> H2 +2OH-. Eo = -0.88 V

Given this information, I would expect to see hydrogen gas at the negative electrode and iron hydroxide at the positive, but when I actually perform it I get oxygen and hydrogen, but no iron hydroxide. Why is this?
 
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Reactions occur in the order from the "easiest" to the "hardest" - so as long as there is water present it will react preferentially.
 
That's what I thought, but it is much easier to oxidize iron than either water or hydroxide according to the values I found... Why do I not get any iron hydroxide?
 
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