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Whats the derivative of sin^2(theta)?

  1. May 10, 2012 #1
    but i need the derivative wrt time where theta depends on time
     
  2. jcsd
  3. May 10, 2012 #2

    Mark44

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    Use the chain rule.
    $$\frac{d}{dt}sin^2(\theta) = \frac{d}{d\theta}sin^2(\theta)\cdot \frac{d\theta}{dt} = ? $$
     
  4. May 10, 2012 #3
    then it is simply 2sin(theta)cos(theta)*(theta dot)
     
  5. May 11, 2012 #4

    Mark44

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    Yes, that's it.
     
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