What's the difference between these 2 graphs?

  • Context: Undergrad 
  • Thread starter Thread starter mathman100
  • Start date Start date
  • Tags Tags
    Difference Graphs
Click For Summary
SUMMARY

The discussion focuses on the transformations of two mathematical graphs, specifically g(x) and h(x). The function g(x) is defined as g(x) = 2f(x/2 + 1), which involves vertical stretching by a factor of 2 and a horizontal stretch by a factor of 2, along with a left shift of 1 and an upward shift of 1. In contrast, h(x) is expressed as h(x) = 4f(x/4 + 5/4) + 2, indicating a different transformation sequence that includes additional vertical and horizontal shifts. The simplification of h(x) reveals that it is not equivalent to g(x) despite some similarities in transformation.

PREREQUISITES
  • Understanding of function transformations in algebra
  • Familiarity with graphing techniques
  • Knowledge of vertical and horizontal shifts
  • Ability to simplify algebraic expressions
NEXT STEPS
  • Study the properties of function transformations in algebra
  • Learn how to graph transformations of functions using Desmos or GeoGebra
  • Explore the concept of function composition and its effects on graph transformations
  • Practice simplifying complex function expressions to identify transformations
USEFUL FOR

Students studying algebra, educators teaching function transformations, and anyone interested in graphing techniques and mathematical analysis.

mathman100
Messages
15
Reaction score
0
I have my original graph f, and I want to make 2 other graphs out of it (each with their own transformations.)
g(x)=2g(1/2x+1)
so it gets stretched vertically by 2, stretched horizontally by 2, goes left 1 and up 1.
But my problem is with h(x)=2[g((x+1)/2)+1)]
What are the transformations made here? Are they the same as g(x)?
 
Physics news on Phys.org
I assume you mean g(x) = 2f(x/2 + 1) and h(x) = 2[g((x+1)/2) + 1]. I don't know why you think that g is vertically shifted (it isn't), but otherwise your description for it is fine.

You can simplify that expression for h(x) to 2g(x/2 + 1/2) + 2. Then substituting in g(x/2 + 1/2) = 2f((x/2 + 1/2)/2 + 1) = 2f(x/4 + 5/4) you get h(x) = 4f(x/4 + 5/4) + 2. That help?

(I am not sure whether I have interpreted your function definitions correctly, so these are just guesses. Are you sure you typed everything out properly? In your post you defined g(x) = 2g(x/2 + 1) which I assume is a typo.)
 
Last edited:

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K