What’s the relation between activity and half-life

AI Thread Summary
The discussion centers on the relationship between activity (A), decay constant (λ), and half-life in radioactive decay. It highlights confusion over two equations: A=λN and A=A0exp^(-λt), particularly regarding how changes in half-life affect these variables. As half-life increases, λ decreases, leading to a decrease in activity according to both equations, but the interpretation of the second equation is debated. A correction is suggested, indicating that the second equation should represent the number of remaining nuclides (N) rather than activity (A). The conversation emphasizes the importance of understanding the behavior of exponential functions in this context.
Angela Liang
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I’m confused because there are two equations:

1) A=λN

2) A=A0exp^-(λt)If half-life increases, λ decreases, and A decreases according to 1); but,

If half life increases, λ decreases, hence exp^-(λt) decreases, A should decreases according to 2)Why is this so? Where went wrong? Thanks!
 
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Angela Liang said:
If half life increases, λ decreases, hence exp^-(λt) decreases

This doesn't look correct. Given the function ##Y=e^{-x}##,
##Y## should increase if ##x## decreases since ##e^{-x}=\frac{1}{e^x}##. Graphing this equation should immediately show you how the function behaves.

Angela Liang said:
1) A=λN

2) A=A0exp^-(λt)

Hmmm. I think the second equation should be ##N=N_0e^{-λt}##, where ##N## is the number of nuclides remaining after time ##t##.
See this page: https://www.miniphysics.com/activity-half-life-and-decay-constant.html
 
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Drakkith said:
This doesn't look correct. Given the function ##Y=e^{-x}##,
##Y## should increase if ##x## decreases since ##e^{-x}=\frac{1}{e^x}##. Graphing this equation should immediately show you how the function behaves.
Hmmm. I think the second equation should be ##N=N_0e^{-λt}##, where ##N## is the number of nuclides remaining after time ##t##.
See this page: https://www.miniphysics.com/activity-half-life-and-decay-constant.html
Thanks!
 
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