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I was working on an experiment for the vapor pressure of water and I have the following formula

ln (p) = -L/(RT) + ln (p_o)

L=heat of vaporization of water

R=Molar gas constant

T=temperature in Kelvins

I have some data points for the pressure p in units of mm Hg, when I take the natural log of it, ln (p), what will the units be? I am very confused...can someone please help me?

When I analyse the units of -L/(RT), it seems like it's dimensionless, but the value of ln (p) definitely depend on the numerical value of p (i.e. having p in different units, e.g. Pa, atm, mm Hg, should give different values of ln (p) ), then how can ln (p) be dimensionless?

Thanks!

ln (p) = -L/(RT) + ln (p_o)

L=heat of vaporization of water

R=Molar gas constant

T=temperature in Kelvins

I have some data points for the pressure p in units of mm Hg, when I take the natural log of it, ln (p), what will the units be? I am very confused...can someone please help me?

When I analyse the units of -L/(RT), it seems like it's dimensionless, but the value of ln (p) definitely depend on the numerical value of p (i.e. having p in different units, e.g. Pa, atm, mm Hg, should give different values of ln (p) ), then how can ln (p) be dimensionless?

Thanks!

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