What's Wrong with this Argument? Understanding the Physics of Work

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SUMMARY

The discussion centers on a physics problem involving work, force, and distance. The teacher's argument that a horizontal force of 15 N applied to a 2 kg block results in a consistent distance of 4/3 m for 20 J of work is challenged. Participants clarify that the calculation neglects factors such as friction and gravity, which are crucial in real-world scenarios. The correct interpretation emphasizes that the resultant force includes both the applied force and any resistive forces, leading to a more nuanced understanding of work in physics.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with the work-energy principle
  • Basic knowledge of friction and gravitational forces
  • Ability to manipulate equations involving work (W=F*d)
NEXT STEPS
  • Study the implications of friction in work calculations
  • Explore the concept of resultant forces in physics
  • Learn about the work-energy theorem in different contexts
  • Investigate how gravity affects motion on inclined planes
USEFUL FOR

Students studying physics, educators seeking clarity on teaching concepts of work and force, and anyone interested in applying theoretical physics to practical scenarios.

Riddl3r
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Homework Statement



Our teacher made an unconvincing argument based on this example:
If a horizontal force of 15 N were a applied to a 2 kg block, and the work done was 20 J, what distance did the object move?

2. The attempt at a solution
Using W=F*d the teacher solved this: 20 J=15 N*x -> x=4/3 m.
This implied that if I applied 15 N to an object of any mass and did 20 J of work, the distance I could move the object is always the same. There seems to be something fundamentally wrong with this statement. But I'm not seeing what it is, I know it's there - I'm think that somehow I need to do something with the weight of the object. I mean if it were to be realistic I would have to calculate friction and gravity too...

Can somebody please tell me what I missed out?
 
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Riddl3r said:
2. The attempt at a solution
Using W=F*d the teacher solved this: 20 J=15 N*x -> x=4/3 m.
This implied that if I applied 15 N to an object of any mass and did 20 J of work, the distance I could move the object is always the same.
That's correct.

Riddl3r said:
There seems to be something fundamentally wrong with this statement. But I'm not seeing what it is, I know it's there - I'm think that somehow I need to do something with the weight of the object. I mean if it were to be realistic I would have to calculate friction and gravity too...

Can somebody please tell me what I missed out?
Usually we neglect friction and the gravity doesn't play a role here because this is a horizontal motion.
 
it's more like a resultant force of 15N which moves the body 4/3 m when 20 J of work is done. the 15 N resultant force may include the force you apply - any resistive forces for example.
 
Oh I see what you're saying, I guess my teacher didn't convey that point very well^^
 

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