Wheatstone Bridge: No Current Flow?

AI Thread Summary
In a Wheatstone bridge, if the potential difference between two points is zero, no current flows through the bridge. This leads to the conclusion that the two ends of the bridge can be connected, simplifying the circuit analysis. When there is no current through a resistor, the potential difference across it is also zero, which confirms the idea of multiple points with the same potential being equivalent. Connecting these points does not change the circuit's outcome, as it results in the same electrical behavior. Thus, the analysis of the Wheatstone bridge can be approached by treating it as a series and parallel combination of resistors.
Faris Shajahan
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In a circuit if the potential difference between two points is zero, no current flows between the two points, right? Or am I wrong? I feel like I am wrong. If I am right, then in a Wheatstone bridge, no current passes through the bridge. Then instead of removing the bridge, why don't we connect the two points?
 
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Faris Shajahan said:
In a circuit if the potential difference between two points is zero, no current flows between the two points, right? Or am I wrong? I feel like I am wrong.

You are correct.

Faris Shajahan said:
If I am right, then in a Wheatstone bridge, no current passes through the bridge. Then instead of removing the bridge, why don't we connect the two points?

What do you mean by "removing the bridge"? What two points do you want to connect?
 
While solving a Wheatstone bridge problem, we removing the bridging resistor and consider it as a parallel combination of series combination of two resistors. (I am sorry if I made it complicated) So what I mean is instead since no current flows through the bridge we can say the potential difference at the two ends of the bridge is zero. Hence why don't we join the two ends of the bridge and consider the whole thing as a series combination of a parallel combination of two resistors?

Btw Am I also correct when I say if there is no current flow through a resistor, then potential difference across the resistor is zero?
 
That would create a node in the middle and allow currents to flow criss-cross, which is not possible with the originial circuit, hence that is a misrepresentation of the circuit.
 
Faris Shajahan said:
Btw Am I also correct when I say if there is no current flow through a resistor, then potential difference across the resistor is zero?
Yes.
Faris Shajahan said:
Hence why don't we join the two ends of the bridge and consider the whole thing as a series combination of a parallel combination of two resistors?
You can. It will give you the same result.
 
cnh1995 said:
Yes.

You can. It will give you the same result.
Ah, yes. Multiple points with the same potential are effectively the same point, makes no difference whether you join them or not.
 
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