Windadct said:
Not sure what you mean by "supply had a really poor power factor", it is the load current (in this case the rectifier) that determines the Power Factor. The whole paragraph has lost me.
Apologies, you've got me worried now, maybe what I'm asking isn't possible. I'll rephrase: say you were using a synchronous generator which is under-excited, which I believe means that the current is leading the voltage, It could just as easily be over-excited for the example. Anyway, you're using this generator to supply your rectifier. So the the power factor of the supply isn't perfect (I'm taking this as axiomatic, please correct me if I'm mistaken). Now, assuming your DC load is purely real, will the DC load voltage and the current both be in-phase with
the current of the synchronous generator?
The other point I was making was to lament that it seems to me based on this thread: if you want to remove the harmonics of the rectifier you're either stuck with the complexity of
active solutions, or the brute simplicity of L and C passive components. There is no middle ground. (a statement for your confirmation)
The other-other point on this note which I was inquiring was: Is an LC filter more effective than 'the sum of it's parts'? I.e. if you took the attenuation of a choke (L)
and separately considered the attenuation of using just a line capacitor (C). And superimposed those attenuations of the harmonics together, would
the theoretical total attenuation of adding the attenuation of L-setup (without capacitor) and the attenuation of C-setup (without inductor) together, be the same as the attenuation seen from using them in conjunction together as an LC filter?
Or does it happen that when you combine them the attenuation is even greater? (I wouldn't expect so, but I'm asking just in case)
I hope this clarifies my last post.
Thanks