$$f(x)=32sin(x+60°)\quad and\quad g(x)=-1.5sin(x+45°)$$(adsbygoogle = window.adsbygoogle || []).push({});

Would the phase angle difference here be 15° or is that incorrect? I think the amplitudes don't have to be the same but I'm not sure if they at least have to be both positive.

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# When getting phase angle difference, do amplitudes have to be positive

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