When Is Kinetic Energy Equal to Rest Energy for a Proton?

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SUMMARY

The speed of a proton when its kinetic energy equals its rest energy is calculated to be approximately 0.866 times the speed of light (c). This conclusion is derived using the relativistic energy equations: K = mc²(γ - 1) and E₀ = mc², where γ is the Lorentz factor. The calculation confirms that γ equals 2, leading to the determination of the proton's speed. This principle applies to any massive particle, not exclusively protons.

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mattst88
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Homework Statement



What is the speed of a proton when its kinetic energy is equal to its rest energy?

Homework Equations



[tex]K = mc^2(\gamma - 1)[/tex]
[tex]E_0 = mc^2[/tex]
[tex]\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}[/tex]

The Attempt at a Solution



[tex]K = E_0[/tex]
[tex]mc^2(\gamma - 1) = mc^2[/tex]
[tex]\gamma = 2[/tex]
[tex]\frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} = 2[/tex]
[tex]0.5 = \sqrt{1 - \frac{v^2}{c^2}}[/tex]
[tex]0.5^2 = 1 - \frac{v^2}{c^2}[/tex]
[tex]c^2 \sqrt{1 - 0.25} = v^2[/tex]
[tex]v = c \sqrt{0.75} = 0.866 c[/tex]

Am I right to use relativistic energy? Have I come to the correct answer? Please advise.
 
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correct (for any massive particle, not just the proton)
 

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