- #1
dancergirlie
- 200
- 0
Homework Statement
What is the speed of a proton after being accelerated to a kinetic energy of 750keV?
Homework Equations
E=K+E0
E0=mc^2
K=(gamma-1)mc^2
gamma=1/(sqroot(1-v^2/c^2))
The Attempt at a Solution
Alright, so to find the speed, I used the equation:
K=(gamma-1)mc^2
which i simplified to:
1/(gamma-1)=mc^2/K
I converted K into joules which is equal to 1.202E-13 J
and what I ended up getting was that
sqroot(1-v^2/c^2) - 1=1250.42
but if i continue on with that I will need to take the square root of a negative number because i will bring v^2/c^2 to the right side and then I would have to do 1-1250.42 and take the square root of that which is undefined. Any help would be great!