When is the Determinant of a Square Matrix Equal to Its Negative?

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SUMMARY

The determinant of a square matrix A, denoted as det(A), is equal to its negative when the size n of the matrix is odd. This conclusion is derived from the property that for any scalar c and matrix A, the determinant is calculated as det(cA) = c^n * det(A). Specifically, when c = -1, the equation simplifies to det(-A) = (-1)^n * det(A), confirming that det(-A) equals -det(A) exclusively for odd-sized matrices.

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Homework Statement



Suppose A is a square matrix of size n. When is det(-A) = -det(A)?

Homework Equations



N/A

The Attempt at a Solution



My approach to the problem is to simply multiply the size n identity matrix by -1, then multiplied by A. For example: det((-1)*IdentityMatrix[n]*A) = det((-1)*IdentityMatrix[n])*det(A). At this point I could answer the original question by saying this is true when n is odd. But I get the impression I am overlooking some other very obvious answer or condition, and am wondering if anyone can think of a different approach. Thanks.
 
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you reasoning seems sound to me...
 
Looks good to me too.

Remember that for scalar c and matrix A, det(cA)=cndet(A) where n is the size of A. Plugging in c = -1 gives your answer.
 

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